The force exerted on the 3.5" piston with a cylinder pressure of 50 psi is:

Prepare for the New Jersey Third Grade Refrigeration Engineer Exam with flashcards and multiple-choice questions. Each question includes hints and explanations. Ace your test today!

To determine the force exerted on the piston, we can use the formula relating pressure, force, and area:

[ \text{Force} = \text{Pressure} \times \text{Area} ]

In this case:

  • The pressure is given as 50 psi (pounds per square inch).

  • The area of the piston must first be calculated based on its diameter. The area of a circle is found using the formula:

[ A = \pi \left( \frac{d}{2} \right)^2 ]

where ( d ) is the diameter of the piston. Substituting the diameter (3.5 inches) into the formula, we find:

  1. Calculate the radius: ( \frac{3.5}{2} = 1.75 ) inches.

  2. Calculate the area:

[ A = \pi (1.75)^2 \approx 3.14 \times 3.0625 \approx 9.621 \text{ square inches} ]

Now using the area to calculate the force:

  1. Calculate the force:

[ \text{Force} = 50 , \text{psi} \times 9.621 ,

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