If you had a compressor operating with a four pole motor at 150hp, 120v, and 60 cycles per second, what would its RPM be?

To determine the RPM (Revolutions Per Minute) of a four-pole motor operating at a frequency of 60 cycles per second (Hz), you can use the formula that calculates synchronous speed:

[ \text{RPM} = \frac{120 \times \text{Frequency (Hz)}}{\text{Number of Poles}} ]

Substituting the values into the formula:

[ \text{RPM} = \frac{120 \times 60}{4} ]

Calculating this gives:

[ \text{RPM} = \frac{7200}{4} = 1800 ]

This result indicates that a four-pole motor running at 60 Hz will have a synchronous speed of 1800 RPM.

Understanding the context of motor operation, a four-pole motor is designed to operate efficiently at 60 Hz, which is the standard frequency in North America for electrical systems. The RPM value calculated refers to the speed at which the motor runs under synchronous conditions, which is typical for an induction motor, enabling it to handle applications such as compressors effectively.